Calculations:
Some examples are given below to show the concept of warping plans.Problem : 01
If Weight of Bag: 50Kg
Total Number of Cone:24 Count: 7OE
Then find out the length of yarn in onecone.
Solution:
Per cone weight = total weight of cone /total no ofcone
=50/24
=2.08333
Length of yarn in one cone = weight ×count
=2.08333×2.20462×840 × 7/1.0936M
=24695.1307M
Answer: Length of 7 OE = 24695M
Problem:02
If Set length:21000m Count: 7 9 12 Ratios:4:4:4
Find out average count.
Solution:
Average Yarn Count= 12 × 7 × 9 × 12 /4 × 9 × 12 + 4 × 7 × 12 + 4 × 7 ×9
=9072/432+336+252
=9072/1020
=8.894
Answer: Average Count =8.89
Problem:03
If, Set length: 24695m
Total ends:4464 Ends/beam:446
Total beam:10 Count: 7OE Find out the weight of yarn required.
Solution:
Weight of yarn in one beam =Set Length × Total Ends × 1.0936/840 × 2.2046 ×count
= 24695 × 446 × 1.0936/840 × 2.20462 ×7
=12044877.592/12963.1656
=929.16Kg
Total yarn required = Weight of yarn in one beam× Total beam
=929.16×10
=9291.61Kg
Answer: Total Yarn Required = 9291.61Kg
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